Special type IV: Clairaut equations

Definition 5 (Clairaut type equations)   A first order PDE is said to be of Clairaut type, if it can be expressed in the form

$\displaystyle u = x u_x + y u_y + f(u_x, u_y).$

The corresponding auxiliary eqs. in Charpit's method:

$\displaystyle \frac{dx}{x + f_{u_x}} = \frac{dy}{y + f_{u_y}} =
\frac{du}{x u_x + y u_y + u_x f_{u_x} + u_y f_{u_y}} =
\frac{du_x}{0} = \frac{du_y}{0}$    

From the last two relations

$\displaystyle u_x = a, \hspace{1cm} u_y = b, \hspace{1cm} ( a, b~$ are constants$\displaystyle ).$

Put these values in the given PDE, one get required complete integral

$\displaystyle u = ax + by + f(a, b).$

Example 1.6.6   Find the complete integral of

$\displaystyle (u_x + u_y)(u - x u_x - y u_y) = 1.$

Solution Rewriting is as,

$\displaystyle u = x u_x + y u _y + \frac{1}{u_x + u_y}.$

This is in Clairaut's form. Therefore, the required complete integral is

$\displaystyle u = ax + by + \frac{1}{a+b}.$