Solution of one-dimensional wave equations by canonical transformation

Consider a one dimensional wave equation

$\displaystyle u_{xx}-c^2u_{tt}=0.$

The discriminant of this equation is $\Delta=4c^2>0.$ Which means given equation is hyperbolic. The characteristic equation are given by solution of

$\displaystyle u(x,t)$ $\displaystyle =\frac{-b\pm \sqrt{b^2-4ac}}{2a},$    
  $\displaystyle =\mp c,$    
$\displaystyle \implies~x\pm ct$ $\displaystyle =$constant$\displaystyle .$    

The canonical variables are

$\displaystyle \xi=x-ct~$and$\displaystyle ~\eta=x+ct,$

$\displaystyle u_x$ $\displaystyle =u_{\xi}+u_{\eta},$    
$\displaystyle u_t$ $\displaystyle =-cu_{\xi}+cu_{\eta},$    

$\displaystyle u_{xx}=(u_{\xi}+u_{\eta})_x=u_{\xi \xi}+2u_{\xi \eta}+u_{\eta \eta},$

$\displaystyle u_{tt}=(-cu_{\xi}+cu_{\eta})_t=c^2u_{\xi \xi}-2u_{\xi \eta}+u_{\eta \eta}.$

Putting it in given equation, one gets

$\displaystyle u_{\xi \eta}$ $\displaystyle = 0,$    
$\displaystyle u_{\xi}$ $\displaystyle =f(\xi),$    
$\displaystyle u$ $\displaystyle =\int f(\xi) d\xi+G(\eta),$    
$\displaystyle u$ $\displaystyle =F(\xi)+G(\eta),$    

$\displaystyle u(x,t)=F(x-ct)+G(x+ct),$ (3.49)

where $F$ and $G$ are arbitrary functions.

   Think it?$\displaystyle ~\begin{cases}
F(x-ct) & \text{wave travelling to right}\\
G(x+ct) & \text{wave travelling to left}
\end{cases} $

To understand motion
  1. Let $u_1(x,t)=F(x-ct).$ The initial wave profile is given by $t=0$ i.e. $u_1(x,0)=F(x).$ Also shown in Fig. [*].
    Figure:
    \includegraphics[width=14cm, height=7.0cm]{imageu.pdf}
  2. Let us understand how this profile evolves as time goes. The trick is to use 'appropriate' time instants.
  3. At $t=\frac{1}{c},~u_1(x,\frac{1}{c})=F(x-1).$ Let $\Tilde{x}=x-1,$ so $F(x-1)=F(\Tilde{x}).$ This shows that the initial wave profile is mentioned, even if the origin is shifted by one unit to the right along the $x-$axis i.e. the graph of $u_1(x,\frac{1}{c})$ is same as the graph of the initial wave profile translated one unit to the right. Also shown in Fig. [*].
    Figure:
    \includegraphics[width=14cm, height=7.0cm]{imageuxc.pdf}
  4. At $t=\frac{2}{c}$, the profile will be shifted by two units to the right of the $x-$axis. Which implies that $F(x-ct)$ is a wave propagating to right.
Now we use analytic solution Eq. ([*]) to solve initial value problem for wave equation.

D'Alembert: Historically, D'Alembert was the first to formulate the equation $u_x=v_y, u_y=-v_x$ during his hydrodynamical investigation. But later, these equations were came to known as C-R equations due to work of Cauchy Riemann to emphasis the equations role w.r.t. compare analytic functions.